Graywd Graywd - 1 year ago 122
C++ Question

Strange swap macro

I typed these code. However, the output is beyond my expectations.

#define SWAP(x,y) {x=x^y;y=x^y;x=x^y;}
#define SWAP2(x,y) {x=x+y;y=x-y;x=x-y;}
int main()
int ia[] = { 1, 10, 1 };
SWAP(ia[0], ia[0]); // the resutl is ia[0] = 0
SWAP(ia[1], ia[2]); // work fine
SWAP2(ia[1], ia[1]) // the result is ia[0] = 0

Anyone can help me? Any help will be appreciated.

Answer Source

Your problem is that your swap algorithms require the two arguments to be separate pieces of memory.

As noted by LYF_HKN, the first step in each algorithm causes x to become 0 when x=y. If the two are merely equal but are still separate pieces of memory, this is fine, because the second step will leave y unchanged (because x is 0), and the third step will restore the original value of x if y is now equal to that original value.

However, when x and y are actually the same object in memory, then the first operation in each algorithm, in setting x to 0, also sets y to 0, since y is x. Thus the rest of each algorithm merely preserves the value 0 in this memory space.

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