EgerStu - 6 months ago 51

C Question

I understand that it's going to take in a number and return a character. I understand what each line of code is doing, but I can't really express what it's doing overall in a meaningful way. Any ideas?

`int function(uint64_t P1)`

{

uint64_t L1 = P1;

uint32_t L2 = 1;

while (L1 > 15){

L2= (uint64_t)L2 << 4;

L1= L1 >> 4;

}

uint32_t L3 = 0;

while (L2 != 0){

L1 = P1;

uint32_t L4 = 0;

L4 = L1 % L2;

uint64_t L5 = (uint64_t)L4;

sub_function(L1/L2);

L3++;

P1 = L5;

L2= (uint64_t)L2 >> 4;

}

L1 = L3;

return L1;

}

void sub_function(uint64_t P1)

{

if (P1<= 9){

printf("%c", P1+48);

}

else{

printf("%c", P1+55);

}

}

Answer

This code accepts a decimal value and prints the hexadecimal representation.

In C++, we can instead use the `std::hex`

stream manipulation flag on `iostream`

to achieve the same result:

```
std::cout << std::hex << 16 << std::endl; // 10
std::cout << std::hex << 42 << std::endl; // 2a
```

Source (Stackoverflow)