AdminBenni - 1 year ago 79
C++ Question

# Check which 2d array elements are closer to each other if the index is represented as x y positions

So I have a two dimensional array that holds some value that doesn't matter.
Let's say that the indexes represent x and y positions on a grid and that I have three points on that grid: The main point and two extra points how do I check which extra point is closest to the main point.
This is the code I tried but it didn't seem to quite work.

``````if(abs(mainX - extra1X) + abs(mainY - extra1Y) < abs(mainX - extra2X) + abs(mainY - extra2Y))
{
cout << "Extra point 1 is closer" << endl;
}
else if(abs(mainX - extra1X) + abs(mainY - extra1Y) > abs(mainX - extra2X) + abs(mainY - extra2Y))
{
cout << "Extra point 2 is closer" << endl;
}
else
{
cout << "They are equally close" << endl;
}
``````

All help is greatly appreciated :)

You are looking for The Distance Formula:

``````double Distance = sqrt(pow((X1 - X2), 2) + pow((Y1 - Y2), 2));
``````

Implement and execute that for both points, then check the value of `Distance` for each point to determine which point is closer.

This should work:

``````double DistanceOne = sqrt(pow((MainX - ExtraXone), 2) + pow((MainY - ExtraYone), 2));
double DistanceTwo = sqrt(pow((MainX - ExtraXtwo), 2) + pow((MainY - ExtraYtwo), 2));

if(DistanceOne < DistanceTwo)
cout << "Point 1 is closer.\n";
else if (DistanceOne > DistanceTwo)
cout << "Point 2 is closer.\n";
else
cout << "Points 1 and 2 are on the same distance from Point Main.\n";
``````
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