Alfredo Osorio Alfredo Osorio -4 years ago 127
Java Question

JPA 2 Criteria Fetch Path Navigation

With JPA 2 Criteria Join method I can do the following:

//Join Example (default inner join)
int age = 25;
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Team> c = cb.createQuery(Team.class);
Root<Team> t = c.from(Team.class);
Join<Team, Player> p = t.join(Team_.players);
c.select(t).where(cb.equal(p.get(Player_.age), age));
TypedQuery<Team> q = entityManager.createQuery(c);
List<Team> result = q.getResultList();


How can I do the same with fetch method, I expected that Fetch interface had get method for path navigation but it doesn't:

//Fetch Join Example

int age = 25;
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Team> cq = cb.createQuery(Team.class);
Root<Team> t = cq.from(Team.class);
Fetch<Team,Player> p = t.fetch(Team_.players);
cq.where(cb.equal(p.get(Player_.age), age)); //This leads to compilation error there is no such method get in interface Fetch
TypedQuery<Team> q = entityManager.createQuery(cq);
List<Team> result = q.getResultList();


According to Hiberante Documentation fetch returns a Join object which is wrong.
http://docs.jboss.org/hibernate/stable/entitymanager/reference/en/html/querycriteria.html#querycriteria-from-fetch

Answer Source

Agree with you about that method, and the fact that you would expect it to allow what you say. Another option would be

Join<Team, Player> p = t.join(Team_.players);
t.fetch(Team_.players);
c.select(t).where(cb.equal(p.get(Player_.age), age));

i.e do a join(), add a fetch() for it, and then make use of the join. This is illogical and only adds to the inelegant nature of JPA Criteria, but anyway, ought to be a workaround

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