kiyo kiyo - 3 months ago 6x
Python Question

How to set class names dynamically?

I have a function that creates classes derived from it's arguments:

def factory(BaseClass) :
class NewClass(BaseClass) : pass
return NewClass

Now when I use it to create new classes, the classes are all named the same, and the instances look like they have the same type:

NewA = factory(ClassA)
NewB = factory(ClassB)
print type(NewA()) # <class __main__.NewClass>
print type(NewB()) # <class __main__.NewClass>

Is the proper fix to manually set the

NewA.__name__ = 'NewA'
print type(NewA()) # <class __main__.NewA>

Are there any other things I should be setting while I'm at it?

Thanks in advance.


Yes, setting __name__ is the correct thing to do; you don't need to set anything else to adjust the class name.

For example:

def factory(BaseClass) :
    class NewClass(BaseClass): pass
    NewClass.__name__ = "factory_%s" % BaseClass.__name__
    return NewClass

type is the wrong thing to use here. It doesn't let you define classes with Python's normal class syntax, instead making you set up every class attribute manually. It's used to create classes by hand, eg. if you have an array of base classes and you want to create a class using it (which you can't do with Python's class syntax). Don't use it here.