BigMac66 BigMac66 - 2 years ago 91
Java Question

Serializing java.util.Date

Does anyone know how a java.util.Date gets serialized? I mean explain to me exactly what each byte is? I tried writing out a long then a date and I can see matches but there are other characters that I just don't get.

Our application makes server requests with data which means it gets serialized from client to server. The team that does stress testing uses a tool that captures these requests and modifies them, the problem is they want to process dates and I don't know how to interpret the byte stream. The dude I am talking to seems willing to learn but so far I haven't found anything that I understand to point him to...

Code I used:

FileOutputStream fos = null;
ObjectOutputStream oos = null;
fos = new FileOutputStream("t.tmp");
oos = new ObjectOutputStream(fos);

Date today = new Date();


catch(FileNotFoundException e)
catch(IOException e)


The output from the above is:

"¬í w ,áqÇ-t Todaysr java.util.DatehjKYt xpw ,áqÇ-x"

The long is "w ,áqÇ-" so what is the stuff between the long and the Date object, i.e. "hjKYt xp"

NOTE some the blanks are unprintable characters NULL, SOH, backspace etc. I understand that it is the hex value that matters.


Still having problems. For some reason the serialized HTTP request does not serialize the date exactly like the answer I accepted says. Very close but still different and I don't know why. What's even odder is that when I simply serialize a date it seems to work fine. FYI at worj we use Websphere 6.1 Here are some examples of what is being sent in the request:




I have been able to identify most fields but not the actual time! E.g the serialVersionUID is


I found the date but it was no where near where I expected it! It was well after the sample I had because other data fields were appearing I thought the date was done - it was just fluke that I noticed the hex pattern of the date I was looking for! Example:


The date value is right at the very end!

Answer Source
 * Save the state of this object to a stream (i.e., serialize it).
 * @serialData The value returned by <code>getTime()</code>
 *         is emitted (long).  This represents the offset from
 *             January 1, 1970, 00:00:00 GMT in milliseconds.
private void writeObject(ObjectOutputStream s)
     throws IOException

therefore, it's the long value representing the offset from Jan 1 1970 00:00:00 GMT in milliseconds.

EDIT: however this is proceeded and succeeded by some headers:

0x73 - being the code for an ordinary object (TC_OBJECT)

0x72 - being the code for a class description (TC_CLASSDESC)

"java.util.Date" - the name of the class

7523967970034938905L - the serialVersionUID

0|0x02|0x01 - flags including SC_SERIALIZABLE & SC_WRITE_METHOD

0 - number of fields


null - there is no superclass descriptor

the time (long milliseconds since epoch)


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